13(13+49)=x^2

Solution for 13(13+49)=x^2 equation:

13(13+49)=x^2

We move all terms to the left:

13(13+49)-(x^2)=0

We add all the numbers together, and all the variables

-x^2+1362=0

We add all the numbers together, and all the variables

-1x^2+1362=0

a = -1; b = 0; c = +1362;
Δ = b2-4ac
Δ = 02-4·(-1)·1362
Δ = 5448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5448}=\sqrt{4*1362}=\sqrt{4}*\sqrt{1362}=2\sqrt{1362}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1362}}{2*-1}=\frac{0-2\sqrt{1362}}{-2}
=-\frac{2\sqrt{1362}}{-2}
=-\frac{\sqrt{1362}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1362}}{2*-1}=\frac{0+2\sqrt{1362}}{-2}
=\frac{2\sqrt{1362}}{-2}
=\frac{\sqrt{1362}}{-1}
$